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![Calculate the percentage loss of mass of hydrated copper [II] sulphate [ CuSO4] when it is completely dehydrated. [ CuSO4· 5H2O→ CuSO4 + 5H2O ][At. wts. are Cu = 64, S = 32, O = 16, H = 1].](https://dwes9vv9u0550.cloudfront.net/images/11410758/5dda324a-d944-43f9-91a8-d67c7e228e40.jpg "Calculate the percentage loss of mass of hydrated copper [II] sulphate [ CuSO4] when it is completely dehydrated. [ CuSO4· 5H2O→ CuSO4 + 5H2O ][At. wts. are Cu = 64, S = 32, O = 16, H = 1].")
Calculate the percentage loss of mass of hydrated copper [II] sulphate [ CuSO4] when it is completely dehydrated. [ CuSO4· 5H2O→ CuSO4 + 5H2O ][At. wts. are Cu = 64, S = 32, O = 16, H = 1].
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Dehydration Of Copper(ii) Sulphate by Jerry Mason/science Photo Library
SOLVED: When copper(II) sulfate pentahydrate (CuSO "5 HzO) is heated, it decomposes to the dehydrated form: The waters of hydration are released from the solid crystal and form water vapor: The hydrated
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